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Dima020 [189]
3 years ago
9

Solve the equation. (-7x + 2)^1/3 = (4 + 3x)^1/3

Mathematics
1 answer:
Brrunno [24]3 years ago
3 0
(-7x + 2)^1/3 = (4 + 3x)^1/3
take the cube of both side to eliminate the 1/3 power
so you get
-7x+2=4+3x
combine like terms
-10x=2
solve for x
x=-1/5
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What is the equation of the line that is perpendicular to the given line and passes through the point (5,3)
Pani-rosa [81]

perpendicular lines have a slope that is a negative reciprocal


A) 4x-5y=5

subtract 4x

solve for y

-5y = -4x+5

divide by -5

y = 4/5 x+5   slope is 4/5  perpendicular slope is -5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = -5/4 (x-5)

B)  5x+4y = 37

subtract 5x

4y =-5x +37

divide by 4

y =-5/4 x +37/4  slope is -5/4 perpendicular slope is 4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = 4/5 (x-5)

C)4x+5y=5

subtract 4x

5y = -4x +5

divide by 5

y = -4/5 x +1

y =-4/5 x +1  slope is -4/5 perpendicular slope is 5/4

y -y1 =m(x-x1)  point slope form of a line

y-3 = 5/4 (x-5)

D)5x-4y=8

subtract 5x

-4y = -5x+8

divide by -4

y = 5/4 x-2

y =5/4 x +-2 slope is 5/4 perpendicular slope is -4/5

y -y1 =m(x-x1)  point slope form of a line

y-3 = -4/5 (x-5)



6 0
3 years ago
What are the value(s) of x for tan(x) = 0?
Nesterboy [21]

Answer:

4.the answer is option four

Step-by-step explanation:

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tan(0)=0

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Who could help me please and thank you
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