Find all the real fourth roots of 256. 4 -8 and 8 8 -4 and 4

1 answer:

3 0

256 = 16^2. In turn, 16=4^2.

The 4th roots are {4, 4, -4 and -4}.

Check for yourself: Does 4^4= 256? does (-4)^4 = 256?

You might be interested in

Write the measure -128 30' 45" as a decimal to the nearest thousandth

miv72 [106K]

Minutes are equal to 1/60ths and seconds are equal to 1/3600ths so

-128+30/60+45/3600

-128.5125

-128.513° (to nearest one-thousandth of a degree)

4 0

2 years ago

Really could use help here.

marishachu [46]

Answer:

$\mathsf {y =\frac{15}{7}x }$ < $\mathsf {y=\frac{13}{6}x }$ < $\mathsf {y=\frac{11}{5}x }$ < $\mathsf {y=\frac{21}{9}x }$ < $\mathsf {y= \frac{19}{8}x}$

Step-by-step explanation:

Finding the unit rate of the graph :

Take 2 points and find the slope
⇒ (0,0) and (12, 25)
⇒ m = 25 - 0 / 12 - 0
⇒ m = 25/12
The equation is : y = 25/12x

Now, the equations with greater unit rates (in increasing order) are :

$\mathsf {y =\frac{15}{7}x }$ < $\mathsf {y=\frac{13}{6}x }$ < $\mathsf {y=\frac{11}{5}x }$ < $\mathsf {y=\frac{21}{9}x }$ < $\mathsf {y= \frac{19}{8}x}$

8 0

1 year ago

What is the range? Please help

jok3333 [9.3K]

Answer:

Step-by-step explanation:

A Cubic Function goes up and down forever, as well as left and right.

3 0

3 years ago

When working through limit problems, why must you write the limit statement every time until you evaluate the equation?

Softa [21]

Because that how it goes

8 0

3 years ago

Find a number such that one-half of the number is 9 less than two-thirds of the number

dimulka [17.4K]

Let's say, the number is "a"
thus $\bf \cfrac{1}{2}a=\cfrac{2}{3}a-9\implies \cfrac{a}{2}=\cfrac{2a}{3}-9\implies \cfrac{a}{2}=\cfrac{2a-27}{3}$

cross-multiply and solve for "a"

3 0

3 years ago