The complete question in the attached figure
Let
for n=1
f(1)=3/8
for n=2
f(2)=3/4
for n=3
f(3)=1 1/8
for n=4
f(4)=1 1/2
for n=5
f(5)=1 7/8
we know that
f(2)-f(1)=3/4-3/8=3/8------> f(2)=f(1)+3/8
f(3)-f(2)=1 1/8-3/4----> 9/8-6/8----> 3/8-----> f(3)=f(2)+3/8
f(4)-f(3)=1 1/2-1 1/8-----> 12/8-9/8----> 3/8-----> f(4)=f(3)+3/8
f(5)-f(4)=1 7/8-1 1/2-----> 15/8-12/8---> 3/8-----> f(5)=f(4)+3/8
therefore
the answer is the optionThe sequence is recursive and can be represented by the function f(n + 1) = f(n) + 3/8
Because yeah I just don’t know that question to the answer so hopefully somebody finds it and you have a good day
Answer:
Step-by-step explanation:
We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.
First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.
Hence, we will have the three factors:
Where <em>a</em> is the leading coefficient.
Expand and simplify the second and third factors:
Hence:
Since f(-1) = 30:
In conclusion, third degree polynomial function is:
Answer:
Sasha can look at the graph and check to see that when she plots the points on the graph, they end up as a straight line. She can also draw a table to test the values and see if when you divide y/x you get the same answer for all of them.
Step-by-step explanation: