The objective is to state why the value of
converging alternating seies with terms that are non increasing in magnitude
lie between any two consecutive terms of partial sums.
Let alternating series
<span>Sn = partial sum of the series up to n terms</span>
{S2k} = sequence of partial sum of even terms
{S2k+1} = sequence of partial sum of odd terms
As the magnitude of the terms in the
alternating series are non-increasing in magnitude, sequence {S2k} is bounded
above by S1 and sequence {S2k+1} is bounded by S2. So, l lies between S1 and
S2.
In the similar war, if first two terms of the
series are deleted, then l lies in between S3 and S4 and so on.
Hence, the value of converging alternating
series with terms that are non-increasing in magnitude lies between any two
consecutive terms of partial sums. So, the remainder Rn = S – Sn alternating
sign
<span> </span>
Answer:
it is 7
Step-by-step explanation:
so i did guess and check
i went two how many time something can go into 28 and i pick four so after you do 2(4)-1 you get 7
so then u add 7 +7 and u get 14 the i just put 7 for the other on b/c ur finding ur perimeter
Answer:
3.14159265358979323846264338327950288419716939937510
58209749445923078164062862089986280348253421170679
Step-by-step explanation:
Thats full 100 digits
Answer:
5x+18
Step-by-step explanation:
9 x 2-8-(-4 x 2-5x)
18-8-(-4 x 2-5x)
18-8-(-5x-8)
18-8+8+5x
Please give Brainliest
The Answer is B
X cannon repeat in a function