Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
<span>-3y+8z your welcome:)</span>
Answer:
1st row 3 down
Step-by-step explanation:
Answer:
16
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
Leg <em>a</em> = <em>a</em>
Leg <em>b</em> = 12
Hypotenuse <em>c</em> = 20
<u>Step 2: Solve for </u><em><u>a</u></em>
- Substitute in variables [Pythagorean Theorem]: a² + 12² = 20²
- Evaluate exponents: a² + 144 = 400
- [Subtraction Property of Equality] Isolate <em>a</em> term: a² = 256
- [Equality Property] Square root both sides: a = 16
