22? (Correct me if I’m wrong)
Answer:
For this exercise we need to solve the next equation:
3 +6x = 2x + 27
We can start substracting 3 at both sides:
3 + 6x - 2 = 2x + 27 - 3
6x = 2x + 25
And then, we can substract 2x::
6x - 2x = 2x + 24 - 2x
4x = 25
Then, we divide by 4:
4x/4 = 24/4
x = 24/4 = 6
Now, we can see if we have done it correctly:
3 + 6*6 = 39
2 * 6 + 27 = 39
And we have seen our result is correct
First let's find how much is 15% of 8500 voters.
To do that, we can multiply 15 by 8500 and then divide by 100.
Work: 15 x 8500 = 127500
127500/100 = 1275
Therefore 15 percent of 8500 is 1275.
Then, we subtract 1275 from 8500 to find the amount of people who did vote.
8500 - 1275 = 7,225
Thus, 7,225 people voted while 1,275 people did not.
Answer:
yes
Step-by-step explanation:
Answer:
a) x = 1225.68
b) x = 1081.76
c) 1109.28 < x < 1198.72
Step-by-step explanation:
Given:
- Th random variable X for steer weight follows a normal distribution:
X~ N( 1154 , 86 )
Find:
a) the highest 10% of the weights?
b) the lowest 20% of the weights?
c) the middle 40% of the weights?
Solution:
a)
We will compute the corresponding Z-value for highest cut off 10%:
Z @ 0.10 = 1.28
Z = (x-u) / sd
Where,
u: Mean of the distribution.
s.d: Standard deviation of the distribution.
1.28 = (x - 1154) / 86
x = 1.28*86 + 1154
x = 1225.68
b)
We will compute the corresponding Z-value for lowest cut off 20%:
-Z @ 0.20 = -0.84
Z = (x-u) / sd
-0.84 = (x - 1154) / 86
x = -0.84*86 + 1154
x = 1081.76
c)
We will compute the corresponding Z-value for middle cut off 40%:
Z @ 0.3 = -0.52
Z @ 0.7 = 0.52
[email protected] < x < [email protected]
-.52*86 + 1154 < x < 0.52*86 + 1154
1109.28 < x < 1198.72
