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3 years ago

Find the 13th term in the following arithmetic sequence 2,5,8,11

Mathematics

1 answer:

givi [52]3 years ago

7 0

Answer:

answer is 38, since she keeps deleting my things

Step-by-step explanation:

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The equation 9x=27 has an answer of x=3. Write down five different equetions with An answer of x=3

Vaselesa [24]

Answer:

Read below.

Step-by-step explanation:

Possible equations with x as 3:

2x=6

3x=9

4x=12

5x=15

10x=30

10+2x=16

4x+32=44

23-5x= 8

42÷2x=7

2x × 2=12

These are just a few possibilities with x as 3.

5 0

3 years ago

You currently pay $10,400 a year for grounds maintenance. it is predicted that competition in the marketplace will force a 3% re

motikmotik

Answer:c= the price will be of $9, 492

Step-by-step explanation:

Hope this helps

4 0

2 years ago

Example of a rational number that is a square root

ipn [44]

Answer:

The list of prime number would probably start with 1 ( 2, 3, 5,7)

4 0

2 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

What is the sum of all the whole numbers from 1 to 1000?

Katen [24]

Answer:

So there are 500 pairs of numbers that have a sum of 1001. Thus, the sum of numbers from 1 to 1000 is 500*1001 = 500,500.

Step-by-step explanation:

5 0

3 years ago