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3 years ago

If the xy-plane, the graph of y=x^2 and the circle with center (0,1) and radious 3 have how many points of intersection?

1 answer:

4 0

<span>The answer to this question is c, two. The top arc of the circle intersects the y=x^2 as each 'limb' extends into infinity. The part of the circle below the x-axis does not intersect the circle. The y=x^2 curve does not dip below the x-axis, but does extend into infinity on both the negative x-axis and positive x-axis.</span>

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What is the solution to the system of equations? (You can either do the substitution or elimination method) x - 2y = 19 x + 3y =

masha68 [24]

Answer:

D. (17,-1)

Step-by-step explanation:

We'll start by canceling out x. To do so, multiple the first equation by -1

-1( x - 2y)=( 19 )(-1)

This gives us:

-x +2y = -19

x + 3y = 14

Add the equations together:

→ 5y = -15

→ y = -1

Plug in y = -1 into an equation:

→ x + 3(-1) = 14

→ x - 3 = 14

→ x = 17

(17,-1)

Hope this helps!

4 0

2 years ago

What are 1x3 and 1x3 combined?

goldenfox [79]

Answer:

it would be 6

Step-by-step explanation:

4 0

3 years ago

52-10=45 Your answer:

prisoha [69]

Answer:

52 - 10 = 42

Step-by-step explanation:

5 0

3 years ago

Tracy needs to find the length and width of the equiptment storage room where she works. the room is 2 meters long than it is wi

ElenaW [278]

Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7

Double check
24 = 2*(5+7) = 2 *12 = 24

4 0

2 years ago

Read 2 more answers

The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard

PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 8.59, \sigma = 0.63$