Answer:
D. (17,-1)
Step-by-step explanation:
We'll start by canceling out x. To do so, multiple the first equation by -1
-1( x - 2y)=( 19 )(-1)
This gives us:
-x +2y = -19
x + 3y = 14
Add the equations together:
→ 5y = -15
→ y = -1
Plug in y = -1 into an equation:
→ x + 3(-1) = 14
→ x - 3 = 14
→ x = 17
(17,-1)
Hope this helps!
Answer:
it would be 6
Step-by-step explanation:
Answer:
52 - 10 = 42
Step-by-step explanation:
Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7
Double check
24 = 2*(5+7) = 2 *12 = 24
Answer:
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.
This is 1 subtracted by the pvalue of Z when X = 9.08. So



has a pvalue of 0.7823
1 - 0.7823 = 0.2177
21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.