SOLUTION:
= 114 - ( - 29 )
= 114 + 29
= 143
Hope this helps! <3
Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
(5+7x)°
(3+9x)°
Step-by-step explanation:
sana makatulong
Step-by-step explanation:
a. g(2) = 2x + 1
2(2) + 1
4 + 1 = 5
b. g(4) = 2x + 1
2(4) + 1
8 + 1 = 9
c, g(-1) = 2x + 1
2(-1) + 1
-2 + 1 = -1
d. g(x) > 2x + 9
9 > 2x + 9
9 - 9 > 2x
0 > 2x
Therefore, x = 0/2
= 0
Answer:
Step-by-step explanation:
