Answer: the probability of a bulb lasting for at most 552 hours is 0.953.
Step-by-step explanation:
Since the life of light bulbs are distributed normally, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the life of light bulbs in hours.
µ = mean hour
σ = standard deviation
From the information given,
µ = 510 hours
σ = 25 hours
We want to find the probability of a bulb lasting for at most 552 hours. It is expressed as
P(x ≤ 552)
For x = 552
z = (552 - 510)/25 = 1.68
Looking at the normal distribution table, the probability corresponding to the z score is 0.953
Answer:
0.2
Step-by-step explanation:
20/100 as a decimal is 0.2.
The solution set is
, meaning that all
at least
satisfy this constraint.
If
, we have
and
, meaning
has to be both greater than and less than
, which is impossible. If
is any greater,
, so
still must be greater and less than
at the same time. So for all
, the system
has no solution.
We have the following equation:
-1/3m - 7 = 5
From here, we must clear the value of m.
We have then:
-1/3m = 5 + 7
-1/3m = 12
1/3m = -12
m = - (3) * (12)
m = -36
Answer:
The value of m is:
m = -36