Answer is: 20.0g H - 20.0 moles; 0.50 g Na - 0.022 moles; 2.0 x 102 mg H2O - 0.011 moles.
1) m(H) = 20.0 g; mass of hydrogen.
n(H) = m(H) ÷ M(H).
n(H) = 20 g ÷ 1 g/mol.
n(H) = 20.0 mol; amount of hydrogen.
2) m(Na) = 0.50 g; mass of sodium.
n(Na) = m(Na) ÷ M(Na).
n(Na) = 0.5 g ÷ 22.98 g/mol.
n(Na) = 0.022 mol; amount of sodium.
3) m(H₂O) = 200 mg ÷ 1000 mg/g.
m(H₂O) = 0.20 g; mass of water.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 0.2 g ÷ 18 g/mol.
n(H₂O) = 0.011 mol; amount of water.
Answer:
as the difference of the energy of the reactants and the energy of the products
Answer is All of the above
Answer:
430 kPa
Explanation:
Use the formula PV/T = PV/T where the left side of the equation refers to the initial values and the right side refers to the final values: (170.2 kPa)(3.5 L)/(298 K) = (P)(1.35 L)/(293 K). The P represents the unknown pressure. Solving this equation gives us a value for P of 433.855 kPa, but because of significant figures (the two from 3.5 L), we round to 430 kPa.
