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Rashid [163]
3 years ago
5

How many solutions does the nonlinear system of equations graphed below have?

Mathematics
2 answers:
Nata [24]3 years ago
8 0

Answer:

The answer is the option A

Four

Step-by-step explanation:

we know that

The solutions of the nonlinear system of equations shown in the graph are equal to the intersection points both graphs

In this problem

The intersection points both graphs are four points

therefore

The systems has four solutions

see the attached figure to better understand the problem

Artemon [7]3 years ago
4 0
I think its 4 because the lines intersect 4 times but its been too long since ive done nonlinear equations
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There were 2430 Major League Baseball games played in 2009, and the home team won the game in 53% of the games. If we consider t
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Answer:

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Step-by-step explanation:

1) Data given and notation  

n=2430 represent the random sample taken

\hat p=0.53 estimated proportion when the home team won the game

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.5 or 50%:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

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3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.53 -0.5}{\sqrt{\frac{0.5(1-0.5)}{2430}}}=2.958  

4) Statistical decision  

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The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.958)=0.0015  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion is significantly higher than 0.5 .  

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