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prohojiy [21]
3 years ago
10

Sierra has a bucket that originally contained 260 fl oz of water and is being filled at a rate of 5 fl oz per minute. Brian has

a bucket that originally contained 650 fl oz of water and is being drained at a rate of 8 fl oz per minute. What is x, the number of minutes that need to pass in order for the two buckets to contain the same amount of water?
5x + 260 = -8x + 650
Mathematics
2 answers:
Evgesh-ka [11]3 years ago
6 0

Answer:

                                               

Step-by-step explanation:

sertanlavr [38]3 years ago
4 0

Answer:

x=30

Step-by-step explanation:

hope this helps

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Novosadov [1.4K]
The GCF of 120 and 36 is 12
6 0
3 years ago
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What is the surface area?<br> 3 ft.<br> 2 ft.<br> SETE<br> 2 ft.<br> .
belka [17]

Answer:

2ft i think if wrong sorry

8 0
3 years ago
Big Mack buys meat for the family reunion cookout. He needs to buy 11 packagesof meat. A package of hotdogs costs $2.59, and a p
IgorC [24]

Hello!

Let's write some important information contained in the exercise:

• hotdogs: $2.59 (,x,)

,

• hamburgers: $5.29 (,y,)

He needs 11 packages. Let's write it:

• x + y = 11

He spent a total of $39.29. We can write it as:

• 2.59x + 5.29y = 39.29

Now, let's solve these two equations as a linear system:

\begin{cases}x+y=11\text{ equation A} \\ 2.59x+5.29y=39.29\text{ equation B}\end{cases}

First, let's isolate x in equation A:

\begin{gathered} x+y=11 \\ x=11-y \end{gathered}

Now, we will replace where's x by 11-y in equation B:

\begin{gathered} 2.59x+5.29y=39.29 \\ 2.59(11-y)+5.29y=39.29 \\ 28.49-2.59y+5.29y=39.29 \\ -2.59y+5.29y=39.29-28.49 \\ 2.7y=10.8 \\ y=\frac{10.8}{2.7} \\  \\ y=4 \end{gathered}

As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.

5 0
1 year ago
Which of the following is a factor of both f(x)=x^2-4x-45 and g(x)=x^2-25
wolverine [178]

Answer:

-5

Step-by-step explanation:

x² - 4x - 45 = 0

(x - 9)(x + 5) = 0

x = 9 or -5

x² - 25 = 0

(x + 5)(x - 5) = 0

x = 5 or -5

-5 is a common factor between both of them

8 0
2 years ago
If the heights of 300 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many studen
Lunna [17]
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation

Calculate z-scores for the following random variable and determine their probabilities from standard tables.

x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088

x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912

x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587

x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413

Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36

Answer: 27

Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36

Answer: 27

Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78

Answer: 204

Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150

Answer: 150

3 0
3 years ago
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