Let’s assume that Laura has x$
Jose = 8+ x
Keith= 3x
So the total is equal to
118= x + 8 +x + 3x
118= 5x + 8
Subtract 8 from both sides
110= 5x
Divide 5 by both sides
22$= x which is what Laura has
Jose will have :8+22= 30$
Keith will have :3*22=66$
Just multiply them together and get a4-2a2-24.
(a2-6)(a2+4)
F: a4
O:4a2
I:-6a2
L:-24
Add together
a4-2a2-24
Answer:
The distance from the base of the statue to the ship is 771.60 ft
Step-by-step explanation:
Refer the attached figure
Height of statue AB= 250 feet
The tourist sees a ship coming into the harbor and measures the angle of depression as 18°.
So, ∠ACB = 18°
We are supposed to find the distance from the base of the statue to the ship i.e. BC
In ΔABC





BC=771.60 ft
Hence the distance from the base of the statue to the ship is 771.60 ft
Answer:
C) 20
Step-by-step explanation:
ab=15
5*3 = 15
which is a and which is b
a - b = +2
5 - 3 = + 2
------------------
a = 5 and
b = 3
------------------
a3-b3 = 53 - 33 = 20
Answer:
a = 8
Step-by-step explanation:
4 : 3 = a : 6

Cross multiply
4*6 = a * 3

a = 4 * 2
a = 8