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igor_vitrenko [27]
3 years ago
8

I need help.. with this worksheet

Mathematics
1 answer:
ipn [44]3 years ago
3 0
8. $298 4. 250 9. 28 6. 8.7 5. 465
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What is the approximate volume of the oblique cone? Use π ≈ 3.14 and round to the nearest tenth. 117.8 cubic units 141.3 cubic u
Tom [10]

Answer:

The answer is 235.5 :)

Step-by-step explanation:

Step-by-step explanation:

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3 years ago
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Find the values of the missing sides in the parallelogram given.
natta225 [31]

Given:

m∠B = 44°

Let's find the following measures:

m∠A, m∠BCD, m∠CDE

We have:

• m∠A:

Angle A and Angle B are interior angles on same side of a transversal.

The interior angles are supplementary.

Supplementary angles sum up to 180 degrees

Therefore, we have:

m∠A + m∠B = 180

m∠A + 44 = 180

Subtract 44 from both sides:

m∠A + 44 - 44 = 180 - 44

m∠A = 136°

• m,∠,BCD:

m∠BCD = m∠A

Thus, we have:

m∠BCD = 136°

• m∠CDE:

Angle C and angle CDE form a linear pair.

Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.

Thus, we have:

m∠D = m∠B

m∠D = 44°

m∠CDE + m∠D = 180

m∠CDE + 44 = 180

Subract 44 from both sides:

m∠CDE + 44 - 44 = 180 - 44

m∠CDE = 136°

ANSWER:

• m∠A = 136°

,

•

,

• m∠BCD = 136°

,

•

,

• m∠CDE = 136°

6 0
1 year ago
Can someone help me with 9,10,11 ?
sergij07 [2.7K]
I could be wrong but i graphed it out and 9 is C , 10 is A , and 11 is C Hopefully it's right
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3 years ago
A box of granola contains 16.8 ounces. It costs $5.19. What is the cost, to the nearest cent, of the granola per ounce?
Keith_Richards [23]

Answer:

$0.3 per ounce.

Step-by-step explanation:

5.19/16.8=0.3

5 0
3 years ago
A recent survey based on a random sample of n=470 voters, predicted that independent candidate for the mayoral election will get
julsineya [31]

I have an expression

\sigma = \sqrt{p(1-p)/n}

floating around in my head; let's see if it makes sense.

The variance of binary valued random variable b that comes up 1 with probability p (so has mean p) is

E( (b-p)^2 ) =  (-p)^2(1-p) + (1-p)^2p = p(1-p)

That's for an individual sample. For the observed average we divide by n, and for the standard deviation we take the square root:

\sigma = \sqrt{p(1-p)/n}

Plugging in the numbers,

\sigma = \sqrt{.24(1-.24)/490} = 0.019 = 1.9\%

One standard deviation of the average is almost 2% so a 27% outcome was 3/1.9 = 1.6 standard deviations from the mean, corresponding to a two sided probability of a bit bigger than 10% of happening by chance.

So this is borderline suspect; most surveys will include a two sigma margin of error, say plus or minus 4 percent here, and the results were within those bounds.

7 0
3 years ago
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