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3 years ago

HELP PLEASE....... FYI: 33 points

Mathematics

1 answer:

makvit [3.9K]3 years ago

3 0

The first question is square or rectangle

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masya89 [10]

Answer: y=4x+6.

Step-by-step explanation:

(-3,-6) k=4 y=kx+b ?

y=4x+b

-6=4*(-3)+b

-6=-12+b

-6+12=-12+12+b

6=b.

Hence,

y=4x+6.

6 0

2 years ago

Triangle ABC has a right angle at C. Select all measurements which would mean it has a hypotenuse with a length of 10 units. a.

Delvig [45]

Option d: Angle A is 30 degrees, BC is 5 units

Option e: AC is 8 units, BC is 6 units

Explanation:

The triangle ABC has a right angle at C.

The length of the hypotenuse is 10 units.

The image of the triangle with this measurement is attached below:

Option a: Angle A is 20 degrees, BC is 2 units

$\begin{aligned}\sin 20 &=\frac{2}{h y p} \\h y p &=\frac{2}{\sin 20} \\&=5.8476\end{aligned}$

Since, hypotenuse is 10 units, Option a is not correct answer.

Option b: AC is 7 units, BC is 3 units

$\begin{aligned}A B &=\sqrt{7^{2}+3^{2}} \\&=\sqrt{49+9} \\&=\sqrt{58}\end{aligned}$

Since, hypotenuse is 10 units, Option b is not correct answer.

Option c: Angle B is 50 degrees, BC is 4 units

$\begin{aligned}\cos 50 &=\frac{4}{h y p} \\h y p &=\frac{4}{\cos 50} \\&=6.222\end{aligned}$

Since, hypotenuse is 10 units, Option c is not correct answer.

Option d: Angle A is 30 degrees, BC is 5 units

$\begin{aligned}\sin 30 &=\frac{5}{h y p} \\h y p &=\frac{5}{\sin 30} \\&=10\end{aligned}$

Since, hypotenuse is 10 units, Option d is the correct answer.

Option e: AC is 8 units, BC is 6 units

$\begin{aligned}A B &=\sqrt{8^{2}+6^{2}} \\&=\sqrt{64+36} \\&=\sqrt{100} \\&=10\end{aligned}$

Since, hypotenuse is 10 units, Option e is the correct answer.

Thus, Option d and e are the correct answers.

3 0

3 years ago

Complete the following statement. If AB = BC and A,B,C are collinear, then b is the BLANK of AC

algol13

Answer:

hi, need help? Call me!! 650-983-3345

Step-by-step explanation:

4 0

3 years ago

X^2-5x-8=0 find the roots (zeros)

melomori [17]

Answer:

$x_1=\dfrac{5-\sqrt{57}}{2}\ ,\quad x_2=\dfrac{5+\sqrt{57}}{2}$

Step-by-step explanation:

$x^2-5x-8=0\\\\a=1\,,\ b=-5\,,\ c=-8\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-8)}}{2\cdot1}=\dfrac{5\pm\sqrt{25+32}}{2}=\dfrac{5\pm\sqrt{57}}{2}$

5 0

3 years ago

Divide: 1,363.5 : 10 = ?

jekas [21]

Answer:

136.35

Step-by-step explanation:

4 0

3 years ago