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julia-pushkina [17]
3 years ago
15

HELP PLEASE....... FYI: 33 points

Mathematics
1 answer:
makvit [3.9K]3 years ago
3 0
The first question is square or rectangle
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Help plz help plz help
nasty-shy [4]
No okokokokokokokokokokokokok
5 0
2 years ago
Read 2 more answers
Help, please (single variable calculus)
balandron [24]

Hi there!

\large\boxed{ 14.875}

Our interval is from 0 to 3, with 6 intervals. Thus:

3 ÷ 6 = 0.5, which is our width for each rectangle.

Since n = 6 and we are doing a right-riemann sum, the points we will be plugging in are:

0.5, 1, 1.5, 2, 2.5, 3

Evaluate:

(0.5 · f(0.5)) + (0.5 · f(1)) + (0.5 · f(1.5)) + (0.5 · f(2)) + (0.5 · f(2.5)) + (0.5 · f(3)) =

Simplify:

0.5( -2.75 + (-3) + (-.75) + 4 + 11.25 + 21) = 14.875

7 0
3 years ago
If you begin a problem with a one digit integer , multiply the number by 4 add 7 divide by 3 subtract 5 and answer of 0 what is
12345 [234]

Answer: imma figure this out

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Plz plz plz help me with this
erica [24]
This question wants you to find a common denominator for the fractions.
This means finding the LCM, least common multiple, for 21 and 9.
This can be done by listing the multiples for each number until they meet at a common one.

9:
9
18
27
36
45
54
63

21:
21
42
63

This means the LCM of 21 and 9 is 63.
So the lowest possible common denominator is 63.

21 • 3 = 63
So you have to multiply the numerator of 2/21 by 3 as well.
2 • 3 = 6
2/21 = 6/63

Now do the same for 1/9.
9 • 7 = 63
Multiply the numerator, 1, by 7.
1 • 7 = 7
1/9 = 7/63

So in the first blanks, you would put 6/63 for what 2/21 is equal to and 7/63 for what 1/9 is equal to.

7/63 is greater than 6/63.
7/63 > 6/63
That means 1/9 > 2/21
So 2/21 < 1/9 is the answer to the last blank.

Hope this helps!
6 0
3 years ago
woodland Mound Park sells annual visitors passes for $12.50. Last year the park raised $53,500 in annual visitors pass sales. Ho
maria [59]

Answer:

4,280\ passes

Step-by-step explanation:

Let

x -----> the number of annual visitors pass sold

we know that

To find out the number of annual visitor passes sold, divide the total amount raised by the cost of a pass.

so

The linear equation that represent this problem is

12.50x=53,500

Solve for x

Divide by 12.50 both sides

x=\frac{53,500}{12.50}=4,280\ passes

5 0
3 years ago
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