Assume that 3 digits are selected at random from the set {1,3,5,6,7,8} { 1 , 3 , 5 , 6 , 7 , 8 } and are arranged in random orde
Mumz [18]
Sample space is 36.so the probability must be 20/36.from three digits the maximum no.of number can be made is 6.
Answer:
x=5
Step-by-step explanation:
x=5
The answer is 21 because 21x21x21= 9261
Answer:

Step-by-step explanation:
Given

<em>See attachment for options.</em>
Required
Determine which of the options answers the question
Analyzing the option one after the other:

Multiply through by y


Divide through by 4


This can be rewritten as


By comparison with 
we have:



<em>Hence: this answers the question.</em>