What is half of 112 cups?

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

What is .9898 as a fraction

AysviL [449]

98 98/100 because you move the decimal point over 2 times

3 0

3 years ago

6/5? Could anyone help me I've been stuck on it for a while. 6 over 5 how do I didvide this and get a ratio?

lora16 [44]

Answer:

6/5 = 1.2 or 6:5

5 0

2 years ago

there are 4 oranges and 2 tangerines in a basket. Which fraction describes the part of the basket that is orange

Pepsi [2]

Answer:

4/6

Step-by-step explanation:

You know that there is a total of 6 fruits in the basket.(you can find the total by adding the number of each item together.)

Then you simply find the total amount of oranges(4).

"There are 4 oranges out of the 6 fruits in the basket"/

So, 4/6.

<em>Hope this helped! :)</em>

6 0

3 years ago

Read 2 more answers

Use quadrilateral ABCD to find the value of x. The figure is not drawn to scale. Use the following dimensions: m⦨ABC = 4x◦, m⦨BC

OLEGan [10]

Answer/Step-by-step explanation:

Question 1:

Interior angles of quadrilateral ABCD are given as: m<ABC = 4x, m<BCD = 3x, m<CDA = 2x, m<DAB = 3x.

Since sum of the interior angles = (n - 2)180, therefore:

$4x + 3x + 2x + 3x = (n - 2)180$

n = 4, i.e. number of sides/interior angles.

Equation for finding x would be:

$4x + 3x + 2x + 3x = (4 - 2)180$

$12x = (2)180$

$12x = 360$

$x = \frac{360}{12}$ (dividing each side by 12)

$x = 30$

Find the measures of the 4 interior angles by substituting the value of x = 30:

m<ABC = 4x

m<ABC = 4*30 = 120°

m<BCD = 3x

m<BCD = 3*30 = 90°

m<CDA = 2x

m<CDA = 2*30 = 60°

m<DAB = 3x

m<DAB = 3*30 = 90°

Question 2:

<CDA and <ADE are supplementary (angles on a straight line).

The sum of m<CDA and m<ADE equal 180°. To find m<ADE, subtract m<CDA from 180°.

m<ADE = 180° - m<CDA

m<ADE = 180° - 60° = 120°

6 0

3 years ago