Question

What is (13-2x)(13-2x) ?

Answer 1

Easy, there are two methods, 

Method One, combine the two common factors of 13-2x by adding the exponents. Making the answer,

(13-2$x)^{2}$

The other method is by multiplying it out, using FOIL (First, Outer, Inner, Last)

switch
(13-2x)(13-2x)
to
(-2x+13)(-2x+13) now you can multiply,

take, FIRST, -2x*-2x
=$4x^{2}$

then, OUTER, -2x*13
=-26x

then, INNER, 13*-2x
=-26x

finally, LAST, 13*13
=169

Finally, add, the sum together.

4$x^{2}$-26x-26x+169

4$x^{2}$-52x+169.

This, is your answer.

Answer 2

(13-2x)(13-2x)

(13+-2x)(13+-2x)

(13)(13)+(13)(-2x)+(-2x)(13)+(-2x)(-2x)

169-26x-26x+4x^2

4x^2-52x+169

I hope that's help !

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