What is (13-2x)(13-2x) ?
2 answers:
Easy, there are two methods,
Method One, combine the two common factors of 13-2x by adding the exponents. Making the answer,
(13-2
The other method is by multiplying it out, using FOIL (First, Outer, Inner, Last)
switch
(13-2x)(13-2x)
to
(-2x+13)(-2x+13) now you can multiply,
take, FIRST, -2x*-2x
=
then, OUTER, -2x*13
=-26x
then, INNER, 13*-2x
=-26x
finally, LAST, 13*13
=169
Finally, add, the sum together.
4
-26x-26x+169
4-52x+169.
This, is your answer.
Method One, combine the two common factors of 13-2x by adding the exponents. Making the answer,
(13-2
The other method is by multiplying it out, using FOIL (First, Outer, Inner, Last)
switch
(13-2x)(13-2x)
to
(-2x+13)(-2x+13) now you can multiply,
take, FIRST, -2x*-2x
=
then, OUTER, -2x*13
=-26x
then, INNER, 13*-2x
=-26x
finally, LAST, 13*13
=169
Finally, add, the sum together.
4
4
This, is your answer.
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Answer:
The graph crosses the x-axis 2 times
The solutions are x = -8 & x = 4
Step-by-step explanation:
Qaudratics are in the form
Where a, b, c are constants
Now, let's arrange this equation in this form:
Where
a = 1
b = 4
c = -32
We need to know the discriminant to know nature of roots. The discriminant is:
If
- D = 0 , we have 2 similar root and there is 2 solutions and that touches the x-axis
- D > 0, we have 2 distinct roots/solutions and both cut the x-axis
- D < 0, we have imaginary roots and it never cuts the x-axis
Let's find value of Discriminant:
Certainly D > 0, so there are 2 distinct roots and cuts the x-axis twice.
We get the roots/solutions by factoring:
Thus,
The graph crosses the x-axis 2 times
The solutions are x = -8 & x = 4