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3 years ago

I need help please?!!!

Mathematics

2 answers:

Solnce55 [7]3 years ago

6 0

Answer:

It should be 15 I calculated it, let me know if this helps :)

topjm [15]3 years ago

5 0

Answer:

Step-by-step explanation:

This of the distance of these two points on a number line. If you were to count the spaces from -1 to -16 you would get 15 spaces. The faster way to do this, however, is if you think of it as a difference.

Subtract the two numbers:

-1-(-16)=-1+16=15

Hope this helps :)

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A wheel barrow can carry up to 300 pounds of weight. A bag of soil wieghs 20 pounds. Write and solve an inequality to respresent

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Let x= the number of bags of soil

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divide both sides by 20 and you get x is less than or equal to 15

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3 years ago

What is the vertex of he graph?

s2008m [1.1K]

Answer:

(1,3)

Step-by-step explanation:

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3 years ago

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Patrick walked 3/5 miles on the first day, 5/7 miles on the second day, third day he walked half of the first day’s distance and

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After the total distance on the first, second and third days, Patrick had walked 3.45miles

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3 years ago

A traingle has vertices at A(-7, 6), B(4, 9), C(-2, -3). What are the coordinates of each vertex if the triangle is translated 4

Alenkinab [10]

Answer:

The coordinates of each vertex are

A'(-3, 0),B'(8,3) and C'(2,-9)

Step-by-step explanation:

we know that

The triangle is translated 4 units right and 6 units down

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The rule for the translation is equal to

(x,y) -------> (x+4,y-6)

Apply the rule of the translation to the coordinates of vertices ABC to obtain the vertices of the image A'B'C'

A(-7, 6) -----> A'(-7+4, 6-6)

A(-7, 6) -----> A'(-3, 0)

B(4, 9) ----> B'(4+4,9-6)

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4 years ago

The length s(t)s(t)s, (, t, )of the side of the base of a square prism is decreasing at a rate of 777 kilometers per minute and

gavmur [86]

Answer:

$\frac{dA_{s}}{dt} = -148\,\frac{km^{2}}{min}$

Step-by-step explanation:

The surface area of the square prism is obtained by using the following formula:

$A_{s} (t) = 4\cdot l(t)\cdot h(t) + 2\cdot [l(t)]^{2}$

The rate of change of the surface area can be found by deriving the function with respect to time:

$\frac{dA_{s}}{dt} = 4\cdot [h(t)\cdot \frac{dl}{dt} + l(t)\cdot \frac{dh}{dt}] + 2\cdot l(t)\cdot \frac{dl}{dt}$

Known variables are summarized below:

$h(t) = 9\,km$

$l(t) = 4\,km$

$\frac{dh}{dt} = 10\,\frac{km}{min}$

$\frac{dl}{dt} = -7\,\frac{km}{min}$

The rate of change is:

$\frac{dA_{s}}{dt} = 4\cdot [(9\,km)\cdot (-7\,\frac{km}{min} )+(4\,km)\cdot (10\,\frac{km}{min} )] + 2\cdot (4\,km)\cdot (-7\,\frac{km}{min} )$

$\frac{dA_{s}}{dt} = -148\,\frac{km^{2}}{min}$

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3 years ago

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