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valentina_108 [34]
3 years ago
9

Plz help due tomorrow

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

The problem is asking for the coefficient of the sum of the two expressions, which are 2/3 and -1/6.

2/3 + -1/6 = 1/2, therefore, the answer is 1/2.

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at a farm the ratio of cows to horses was 7:2 if there were 21 cows at the farm how many horses were there
allochka39001 [22]
6

Ratio can be rate but rate can never be ratio. In essence, rate is comparison between ratios.  While ratio is comparison between two or more numbers. Further, ratio on one hand, involves numbers either in amount, size, measurement, degrees, percentages or fractions with the absence of specific unit of measurement. On the contrary, rate is comparing quantities, amounts or unit of events happened expressed in a specific measurement or expressed under time. Take for instance, an example, Joe eats 2 while John eats 4 meals in a day. The ratio can be Joe: John, 2:4 meals. While the rate, is Joe eats 2 meals/day and John 4 meals/day. 

3 0
3 years ago
Find the simplified product ^3 sqrt 9x^4 * ^3 sqrt 3x^8
AleksAgata [21]

\bf ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt[3]{9x^4}\cdot \sqrt[3]{3x^8}\implies (9x^4)^{\frac{1}{3}}\cdot (3x^8)^{\frac{1}{3}}\implies 9^{\frac{1}{3}}\cdot x^{4\cdot \frac{1}{3}}\cdot 3^{\frac{1}{3}}\cdot x^{8\cdot \frac{1}{3}}

\bf 9^{\frac{1}{3}}\cdot 3^{\frac{1}{3}}\cdot x^{\frac{4}{3}}\cdot x^{\frac{8}{3}}\implies (3^2)^{\frac{1}{3}}\cdot 3^{\frac{1}{3}}\cdot x^{\frac{4}{3}+\frac{8}{3}}\implies 3^{\frac{2}{3}}\cdot 3^{\frac{1}{3}}\cdot x^{\frac{12}{3}} \\\\\\ 3^{\frac{2}{3}+\frac{1}{3}}x^4\implies 3^{\frac{3}{3}}x^4\implies 3x^4

6 0
4 years ago
Read 2 more answers
Please help mee
Bess [88]

Answer:

$47,616

Step-by-step explanation:

49,600 x .04 = 1984

49,600- 1984 = $47,616

5 0
3 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t^3 + 21t^2 + 60t + 3 for t ≥ 0 with t measured in
natta225 [31]
As the fellow above said, the particle does make a U-turn at the vertex, and we can find that out by getting the derivative of s(t) and zeroing it out to get the point of the horizontal tangent.

Bearing in mind that ds/dt is really v(t) or the velocity equation, so when we zero out the ds/dt, is the same as saying the velocity went to 0, since it got zeroed out, and then the particle goes over the vertex and changes direction.

\bf s(t)=2t^3-21t^2+60t+3\implies \boxed{\cfrac{ds}{dt}=6t^2-42t+60}\leftarrow v(t)
\\\\\\
0=6t^2-42t+60\implies 0=t^2-7t+10\implies 0=(t-5)(t-2)
\\\\\\
t=
\begin{cases}
5\\
2
\end{cases}\impliedby \textit{it makes the first turn at the \underline{2 second}}
\\\\\\
\textit{now let's find the acceleration equation, a(t)}
\\\\\\
\boxed{\cfrac{d^2s}{dt^2}=12t-42}\leftarrow a(t)\\\\
-------------------------------\\\\
s(2)=55\qquad \qquad \qquad \qquad a(2)=-18

the negative acceleration value, simply means a decreasing rate of change, so, it means the particle is slowing down and possibly coming to a stop before changing direction again.
8 0
3 years ago
If r(x) = 3x - 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?
zavuch27 [327]

Answer:

17/13

Step-by-step explanation:

r(6) = 3(6) - 1 = 17 and s(6) = 2(6) + 1 = 13.

Then (r/s)(6) = 17/13.

4 0
4 years ago
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