Given :
Two equation 
and 
.
To Find :
The point of intersection of these lines .
Solution :
We will use elimination method :
From equation 1 :
Putting value of 
in equation 2 we get :
Putting value of 
in equation 1 we get :
Therefore , point of interaction is 
.
Hence , this is the required solution .
Answer:
It does work.
Step-by-step explanation:
Answer:
it's density is 8 g /cm³
Step-by-step explanation:
Mass (m) = 96 g
Volume (v) = 12 cm³
Density (d) =?
We know density is defined as mass per unit volume so
d = m/v
= 96 / 12
= 8 g/cm³
Hope it will help :)
Note : if in the question it is said to write in sI system u have to write in kg/m³.
Answer:
y''=-1.26
Step-by-step explanation:
We are given that 
We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.
Differentiate w.r.t x
Then , we get
Again differentiate w.r.t.x
Then , we get
Using value of y'
Substitute x=2 and y=3
Then, we get 
Hence,y''=-1.26
Answer:
- 7
Step-by-step explanation:
6(- x - 3) = 24
-6x - 18 = 24
-6x = 24 + 18
-6x = 42
x = 42 ÷ - 6
x = - 7
