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n200080 [17]
2 years ago
6

Simplify.

Mathematics
1 answer:
aleksley [76]2 years ago
5 0
First multiply (-5/6) and (1/6) to get
-  \frac{5}{36}
then you subtract that from (8/9) to get
\frac{27}{36}
final answer is
\frac{3}{4}
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Maddox wants to go back to college full-time. His current employer has agreed to reduce his hours from 40 hours to 25 hours whil
4vir4ik [10]

Answer:

Best fit for his new situation is modified budget A

Step-by-step explanation:

lets first calculate Wages which will be earned by Maddox after reduction of working hours .

from his current situation we can say that ,

for working of 40 hours ,  Maddox monthly income wages = $1760

so  for working of 1 hour , Maddox monthly income wages = $1760÷40=$44

hence for working of 25 hour , Maddox monthly income wages will be $44 × 25 = $1100.

So New wages after reduction of working hours will be $1100. but if you see , in budget B and C , Income wages is considered as $1600 which will not be case after reduction of working hours to 25 . hence Maddox cannot go for Modified Budget B and Modified Budget C.

So he needs to decide between Modified Budget A and Modified Budget D.

Now lets concentrate upon Net income for Modified Budget A and Modified Budget D. Net income for Modified Budget D is in negative that is -$515. that means he need to earn $515 more to meet Budget D , but income wages are fixed that is $1100.

At last lets see Net income of modified budget A. he is able to save $30 , hence we can say that best fit for his new situation is modified budget A


8 0
3 years ago
Read 2 more answers
Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a
Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q  = -t/100 + c

Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c}  = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}

when t = 0, Q = 200 L × 1 g/L = 200 g

Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

2 = 200e^{(-t/100)}\\\frac{2}{200} =  e^{(-t/100)}

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0
3 years ago
A bag contains 26 tiles, each with a different letter of the alphabet written on it. You choose 3 tiles from the bag without loo
blagie [28]

Answer:

1/26

Step-by-step explanation:

Total no. of tiles = 26

In each tile , a different alphabet is written.

And we need 3 tiles (in which A , B & C are written in it) in one try.

So the probability of choosing tiles with letters A , B & C ( in one try ) = 1/26

4 0
2 years ago
Find f(4) for the function below. <br><br> f(x) = |x-7| + 3
Anastaziya [24]

Step-by-step explanation:

f(x) = |x-7| + 3

when x is equal to 4, then

f(4) = |4-7| + 3

=-3+3

=0

6 0
2 years ago
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You are hosting a convention for a charitable organization. You pay a rental fee of $28,500 for the convention center, plus you
Alexxandr [17]
You have to add the $51 to $13 and find the answer then divide the sum by $28,500
8 0
3 years ago
Read 2 more answers
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