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Montano1993 [528]

3 years ago

9

Given a mean of 4.5 and a standard deviation of 12 from a sample of variables, what is the equivalent draw from a standard norma

l distribution for 6.0?

1 answer:

IRINA_888 [86]3 years ago

4 0

Hsijhshhdonbcfdjjbdjdkkdnnd

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What is the word form for 2.51 and expanded form

Nimfa-mama [501]

Word Form:
Two and fifty-one hundredths

Expanded Form:
2 + 0.5 + 0.01

Hope I Helped You!!! :-)

Have A Good Day!!!

6 0

3 years ago

A) Write an expression for the slope of the secant line through the points

Crazy boy [7]

Answer:

Step-by-step explanation:a/

slope m = [f(x)-f(3)]/(x-3)

b/

tangent y - f(3) = [lim m ,as x-->3](x-3)

7 0

2 years ago

Why is the point of intersection for a system of equations<br> considered its solution?

meriva

Answer:

because they never touch

8 0

3 years ago

Read 2 more answers

Sets M and F are defined as follows.

a_sh-v [17]

Answer:

intersection is /c,d/

Step-by-step explanation:

circle the common members and list them

6 0

3 years ago

Assuming that the sample mean carapace length is greater than 3.39 inches, what is the probability that the sample mean carapace

joja [24]

Answer:

The answer is "".

Step-by-step explanation:

Please find the complete question in the attached file.

We select a sample size n from the confidence interval with the mean $\mu$ and default $\sigma$ , then the mean take seriously given as the straight line with a z score given by the confidence interval

$\mu=3.87\\\\\sigma=2.01\\\\n=110\\\\$

Using formula:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

The probability that perhaps the mean shells length of the sample is over 4.03 pounds is

$P(X>4.03)=P(z>\frac{4.03-3.87}{\frac{2.01}{\sqrt{110}}})=P(z>0.8349)$

Now, we utilize z to get the likelihood, and we use the Excel function for a more exact distribution

$=\textup{NORM.S.DIST(0.8349,TRUE)}\\\\P(z$

the required probability: $P(z>0.8349)=1-P(z$

4 0

2 years ago