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Natasha_Volkova [10]
3 years ago
8

Please answer ASAP! An explanation is a MUST REQUIREMENT in order to receive points and the Brainliest answer. Thank you.

Mathematics
1 answer:
galben [10]3 years ago
3 0
Remmber pemdas or gemdas or bodmas or whatever

exponential laws
(x^m)^n=x^(mn)

ok so

(3^2)(2a)^(3/2))^2=
(3^2)(2a)^((3/2)*2)=
(3^2)(2a))^(6/2)=
(3^2)(2a)^3=
(3^2)(8a^3)^3=
(9)(8a^3)=
72a^3

2nd one from left
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A geometric sequence has an initial value of 2 and a common ratio of 3. Which formula would be more practical to use if you were
Makovka662 [10]

Answer:

19th term = ar^18

19th term = 774,840,978

Step-by-step explanation:

First term, a = 2

Common ratio, r = 3

nth term of a geometric sequence = ar^(n-1)

19th term = ar^(19-1)

19th term = ar^18

= 2 × 3^18

= 2 × 387,420,489

= 774,840,978

19th term = 774,840,978

8 0
3 years ago
1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
Emily bought 4 cheeseburgers for $6 each and then spent $18 on a new shirt. She paid for the cheeseburgers and shirt with her de
Soloha48 [4]
-42 would be the answer
8 0
2 years ago
Read 2 more answers
Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) . Write the coordinate notation for a translation of 8 units right
Dovator [93]
Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .

Rule: (x, y)→(x + 8, y + 1 )

J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)


J’ (6,3)
K’ (5,-3)
L’ (9,-1)


Hope this helps!
3 0
2 years ago
Please solve the math question: |4x−4(x+1)|=4
alexgriva [62]

Answer:

x has infinite solutions

Step-by-step explanation:

|4x−4(x+1)|=4

Simplify inside the absolute value by distributing the 4

|4x−4x+4|=4

Combine like terms

|4|=4

The absolute value of 4 is 4

4=4

This is always true, so x is all real values

x has infinite solutions

3 0
3 years ago
Read 2 more answers
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