<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
Answer:
Arithmetic sequence.
Step-by-step explanation:
We have been given a sequence : -2, 0, 2, 4, 6. We are asked to define the type of our given sequence.
We can see from our given sequence that each next term is 2 more than the previous term of the sequence.
Since the difference between the consecutive terms is constant and each next term is produced by adding 2 to preceding term, therefore, our given sequence is an arithmetic sequence.
Answer:
-8d+13
Step-by-step explanation:
Add and Multiply all of the numbers without variables:
3x4+1
Use PEMDAS to solve (Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction):
3x4=12
12+1=13
Now you have your answer:
-8d+13
