In order to organize your work effectively on the computer, where is the best place to save it?

A and B have same output or not? A B x=0 x=0 do do x<3 x=x+1 x=x+1 print x print x while x<3 while

katen-ka-za [31]

Answer:

A and B have different output:

A output will be 1

B output will be 123

Explanation:

A

X = 0

do x < 3

x = x+1

print x

while

B

X = 0

do x = x+ 1

print x

while x < 3

For statement A the condition statement which suppose to be after "while" is not set therefore the value of x will be printed.

For statement B the condition statement is set "x < 3" in front of "while" thereby result in iteration until the condition is false.

Statement A output will be 1

Statement B output will be 123

6 0

3 years ago

Given that Jamie worked 50 hours (Hours = 50) last week and earns $10.00 an hour (Rate = 10), how much did Jamie earn last week,

quester [9]

Answer:

Jamie earned (Total pay) $500.

Explanation:

We are given the following code:

If (Rate >=10) OR (Hours <=40) Then

TotalPay = Hours * Rate

Else

TotalPay = (Hours * Rate)+(Hours–40)*Rate*1.5

End If

Let us understand the code line by line:

The first line contains an if statement with 2 conditions:

i.e. 1st condition:

The rate is greater than or equal to 10

2nd condition:

Number of hours are lesser than or equal to 40.

There is OR between the two condition i.e. the statement next to if() statement will get executed if any one of them becomes true and else part will not be executed.

The next statement is:

TotalPay = Hours * Rate

It calculates the pay if any of the two conditions written earlier becomes true.

Next statement is else statement:

It will get executed given that the above if() statement becomes false.

Now, we are given that Jamie worked 50 hours last week and earns $10.00 an hour:

i.e.

Hours = 50

Rate = 10

Now, let get to the code execution.

The first condition is true i.e. Rate >= 10 (because Rate is 10 here)

So, the following statement will be used to calculate the Total pay:

TotalPay = Hours * Rate

and else part will not be executed.

TotalPay = 50 * 10 = $500

Jamie earned (Total pay) $500.

3 0

2 years ago

Arrange the steps for conflict resolution in proper sequence.

VashaNatasha [74]

1.Clarify what the disagreement is

2. Establish a common goal for both parties

3. Discuss ways to meet the common goal

4. Determine the barriers to the common goal

5. Agree on the best way to resolve the conflict

6. Acknowledge the agreed upon solution and determine the responsibilities each part has in the resolution

8 0

3 years ago

Read 2 more answers

A 3D printer has at least how many stepper motors?

lyudmila [28]

I believe it is 200 per revolution!

4 0

3 years ago

Write a program that lets the user enter the total rainfall for each of 12 months (starting with January) into an array of doubl

lianna [129]

Answer:

The C++ code is given below with appropriate comments

Explanation:

#include "stdafx.h"

//Header file section

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

//Function prototypes

double rainfallTotal(double[], int);

double averageMonthlyRainfall(double[], int);

double highestAmountRainfall(double[], int, int &);

double lowestAmountRainfall(double[], int, int &);

int main()

{

//Initialize variables

const int ALL_MONTHS = 12;

int highIndex = 0;

int lowIndex = 0;

//Declare variables

double totalRf;

double averageRf;

double mostRf;

double leastRf;

double monthlyRf[ALL_MONTHS];

string monthName[ALL_MONTHS] = { "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December" };

for (int i = 0; i < ALL_MONTHS; i++)

{

cout << "Enter rainfall for " << monthName[i] << ": ";

cin >> monthlyRf[i];

// Check the input as negative numbers

//for monthly rainfall

while (monthlyRf[i] < 0)

{

cout << "Invalid data (negative rainfall) " << endl;

cout << "Retry the rainfall in " << monthName[i] << ": ";

cin >> monthlyRf[i];

}

//Call the methods

totalRf = rainfallTotal(monthlyRf, ALL_MONTHS);

averageRf = averageMonthlyRainfall(monthlyRf, ALL_MONTHS);

mostRf = highestAmountRainfall(monthlyRf, ALL_MONTHS, highIndex);

leastRf = lowestAmountRainfall(monthlyRf, ALL_MONTHS, lowIndex);

//Display output

cout << fixed << showpoint << setprecision(2) << endl;

cout << "Total rainfall: " << totalRf << endl;

cout << "Average rainfall: " << averageRf << endl;

cout << "Least rainfall in " << monthName[lowIndex] <<endl;

cout << "Most rainfall in " << monthName[highIndex] <<endl;

system("pause");

return 0;

}

//Method definition of rainfallTotal

double rainfallTotal(double totalRainfall[], int n)

{

double total = 0;

for (int i = 0; i < n; i++)

total += totalRainfall[i];

return total;

}

//Method definition of averageMonthlyRainfall

double averageMonthlyRainfall(double totalRainfall[], int n)

{

double average = 0.0;

double total = 0;

for (int i = 0; i < n; i++)

total += totalRainfall[i];

average = total / n;

return average;

}

//Method definition of lowestAmountRainfall

double lowestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double least;

int i = 0;

least = totalRainfall[i];

while (i < n)

{

if (totalRainfall[i] < least)

{

least = totalRainfall[i];

monthIndex = i;

}

i++;

}

return least;

}

//Method definition of highestAmountRainfall

double highestAmountRainfall(double totalRainfall[], int n, int &monthIndex)

{

double high;

int i = 0;

high = totalRainfall[i];

while (i < n)

{

if (totalRainfall[i] > high)

{

high = totalRainfall[i];

monthIndex = i;

}

i++;

}

return high;

}

3 0

2 years ago