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Mathematics

1 answer:

Paha777 [63]3 years ago

6 0

Answer:

Step-by-step explanation:

∠QSR = 180° - 150° = 30° ( straight angle )

tanQSR = tan30° = $\frac{1}{\sqrt{3} }$ = $\frac{\sqrt{3} }{3}$ → A

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The savings account offering which of these APRs and compounding periods

Ann [662]

Answer:

The answer is "Option C"

Step-by-step explanation:

The using formula $= (1+\frac{r}{n})^n -1$

→r = rate

→ n = compounded value

In choice a:

When compounded is monthly $4.0784\%$

$n = 12$

$\to (1+ \frac{0.040784}{12})^{12} = 1.0403-1 = 0.0403$

In choice b:

When compounded is quarterly $4.0792\%$

$n = 3\\\\\to (1+ \frac{0.040792}{12} )^{3} = 1.0102-1 = .0102$

In choice c:

Whenn compounded is daily $4.0730 \%$

$n = 365\\\\\to (1+ \frac{0.040730}{12})^{365} = 3.328-1 = 2.328$

In choice d:

When compounded is semiannually $4.0798\%$

$n = 2\\\\\to (1+ \frac{0.040798}{12})^{2} = 1.0066-1 = 0.0066$

7 0

2 years ago

Read 2 more answers

Which equation are true for x=-2 and x=2 check all that apply

ki77a [65]

1 it is true
${x}^{2} - 4 = 0 \\ {x}^{2} = + 4 \\ x = \sqrt{4} = 2$
2 it's not true
${x}^{2} = - 4$
3 it's not true
$3 {x}^{2} + 12 = 0 \\ 3 {x}^{2} = - 12 \\ {x}^{2} = \frac{ - 12}{3} = - 4 \\$
4 it's true
$4 {x}^{2} = 16 \\ {x}^{2} = \frac{16}{4} = 4 \\ x = \sqrt{4} = 2$
5- it's true
${2(x - 2)}^{2} = 0 \\ {(x - 2)}^{2} = 0 \\ x - 2 = 0 \\ x = 2$