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Murljashka [212]
3 years ago
14

Again, math is my worst subject.

Mathematics
1 answer:
UNO [17]3 years ago
7 0
No it is not the worst subject
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Select all the options below that correctly fill in the blank. A ____ is a subcategory of polygon.
bixtya [17]

Answer:

A triangle and an octagon

Step-by-step explanation:

Let me know if either one of them is wrong

5 0
2 years ago
PLEASE HELP❗<br> 5<br>8 × 10 is how many times as great as<br> -1<br>8 × 10​
antoniya [11.8K]

Answer:

10⁶

PLZ MARK AS BRAINLIEST(if i am correct)

6 0
2 years ago
Read 2 more answers
Helppppppppp pleaseeeeeeeeeee
djyliett [7]

Answer:

ok

Step-by-step explanation:

5 0
3 years ago
Question 1,2, and 3 how do i factor those? Can you show the work and explain how?
DiKsa [7]

1: 3n^{2}+9n+6

notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

3(n^{2} +2n+n+2)

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

2: 28+x^{2} -11x

So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

x^{2} -4x-7x+28

now we can factor out x from the first expression and -7 from the second

x(x-4)-7(x-4)

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to x^{2} -11x+28

3: 9x^{2} -12x+4

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as 3^{2} and 4 as 2^{2}, the equation becomes

3^{2} x^{2} -12x+2^{2}

now that 3^{2} x^{2} is ugly so it can be turned into (3x)^{2}

and -12x can be rewritten as -2*3x*2

so our equation now looks like (3x)^2-2*3x*2+2^{2}

There's a rule that says a^{2} -2ab+b^{2} = (a-b)^{2}

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

(3x-2)^2

5 0
2 years ago
Can you please explain how to solve this?
BlackZzzverrR [31]

Answer:

18

Step-by-step explanation:

hello,

as this is a parallelogram we can write that BE = DE so

15x + 4 = 9x + 6

<=> 15x - 9x + 4 = 6

<=> 6x = 6 - 4 = 2

<=> x = 2/6 = 1/3

so BE = DE = 15/3+4=5+4=9

so BD = BE + DE = 9 + 9 = 18

the correct answer is 18

hope this helps

7 0
3 years ago
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