well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)
![f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k](https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cbegin%7Bcases%7D%207x%2Bk%2C%26x%5Cleqslant%202%5C%5C%20kx%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20f%282%29%3D%20%5Cbegin%7Bcases%7D%207%282%29%2Bk%2C%26x%5Cleqslant%202%5C%5C%20k%282%29%5E2-6%26x%20%3E%202%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%207%282%29%2Bk~~%20%3D%20~~k%282%29%5E2-6%5Cimplies%2014%2Bk~~%20%3D%20~~4k-6%20%5C%5C%5C%5C%5C%5C%2014~~%20%3D%20~~3k-6%5Cimplies%2020~~%20%3D%20~~3k%5Cimplies%20%5Ccfrac%7B20%7D%7B3%7D%3Dk)
Answer:
The ounces of oil needed is 5 ounces of oil
Step-by-step explanation:
The first thing to do here is to calculate the volume of the lemon-scented candle given.
Looking at shape the volume can be calculated using the formula L * B * H
where L(length) = 10cm , B(breadth) = 8cm and Height(h) = 25cm
The volume V is thus = 10 * 8 * 25 = 2,000 cm^3
The ounces of oil needed for the candle to have 0.0025 ounces of oil per cm^3 of wax will be = The volume of the lemon-scented candle * 0.0025 ounces of oil per cm^3 of wax
That will be = 0.0025 * 2,000 = 5 ounces
It should go like this:
(4z + 3) (3z - 4) / (3z - 4) (z + 2)
Then you just cancel out (3z -4) and (3z -4), and the final simplified form of this polynomial is:
(4z +3) / (z + 2)
Answer:
the 3rd one
Step-by-step explanation:
Answer:
Don't fail
Step-by-step explanation:
