To calculate the distance between 2 points we will use the following equation:
![D=\sqrt[]{(x_2-x_1)^2-(y_2-y_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2-%28y_2-y_1%29%5E2%7D)
For this exercise we have the following data:

We plug the values into the distance equation and solve for the unknown Y
Answer:

Step-by-step explanation:
Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:
First airplane

Where t is the time measured in hours.
Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

Rate of change of such distance can be found by the deriving the expression in terms of time:

Where
and
, respectively. Distances of each airliner at 2:30 PM are:


The rate of change is:


3- 2b +4 = 2-7b
3+4 = 2 - 5b
7 = 2 -5b
5 = -5b
-5b /-5 = -1
b = -1
This is my expression: 45h + 125. I hope this helps.
Answer:
Answer is 10 degrees Celsius.
Step-by-step explanation:
The x value or Fahrenheit is 50 at the same spot the y value is 10