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Nitella [24]
3 years ago
11

A missing fraction on a number line is located exactly halfway between 3/6 and 5/6

Mathematics
1 answer:
Dominik [7]3 years ago
8 0
The missing fraction would be \frac{4}{6} since it is exactly in the halfway between \frac{3}{6}  and \frac{5}{6}
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vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function f(x)=1/x. We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b}  =-1/8

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

\frac{.5b-1}{2b-b^2} =\frac{-1}{8}

Now, cross multiply.

4b-8=b^2-2b

b^2-6b+8=0

Solve for b. Factor using the numbers -4 and -2.

=(b-4)(b-2)=0

Thus, b=4 or b=2.

However, b=2 is not a possible solution since the interval [2,2] means nothing. Thus, b=4.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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