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Agata [3.3K]
3 years ago
8

Which relation represents a function? StartSet (0, 0), (2, 3), (2, 5), (6, 6) EndSet StartSet (3, 5), (8, 4), (10, 11), (10, 6)

EndSet StartSet (negative 2, 2), (0, 2), (7, 2), (11, 2) EndSet StartSet (13, 2), (13, 3), (13, 4), (13, 5) EndSet
Mathematics
2 answers:
postnew [5]3 years ago
8 0

Answer:

<h2>Third set.</h2>

(-2, 2), (0, 2), (7, 2), (11, 2)

Step-by-step explanation:

A function is defined as a relation where each x-value (domain), has only one y-vale assigned (range). If one x-value has more than one image in the range, therefore, that's not a function. So, let's see which relation represents a function.

First: (0, 0), (2, 3), (2, 5), (6, 6).

As you can see, this set doesn't represent a function, because for x=2 there are two images assigned y=3 and y=5.

Second: (3, 5), (8, 4), (10, 11), (10, 6).

Similarly, this relation is not a function, because x=10 has to images, y=11 and y=6.

Third: (-2, 2), (0, 2), (7, 2), (11, 2)

As you can see, this is a function, because each pair has different value in the domain. Notice that there's the same image for each x-value, that still fulfil the definition of a function, because one element in the image can have multiple elements in the domain, what cannot happen is the opposite case.

Fourth: (13, 2), (13, 3), (13, 4), (13, 5).

This relation is not a function, because the same x-value has multiple images.

Therefore, the right answer is the third set.

butalik [34]3 years ago
8 0

Answer:the third one

Step-by-step explanation:no x values repeat, therefore it is a function.

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