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CaHeK987 [17]
3 years ago
12

8-5c=-37 help please :)

Mathematics
2 answers:
ladessa [460]3 years ago
6 0

Answer:

c=9

Step-by-step explanation

8-5c=-37

-37-8= -5c

-45= -5c

-45/-5=c

c=9

gavmur [86]3 years ago
5 0

Answer:

c = 9

Step-by-step explanation:

Given

8 - 5c = - 37 ( subtract 8 from both sides )

- 5c = - 45 ( divide both sides by - 5 )

c = 9

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Suppose that x is the probability that a randomly selected person is left handed. The value (1-x) is the probability that the pe
harina [27]

Answer:

The maximum variance is 250.

Step-by-step explanation:

Consider the provided function.

V(x)=1000x(1-x)

V(x)=1000x-1000x^2

Differentiate the above function as shown:

V'(x)=1000-2000x

The double derivative of the provided function is:

V''(x)=-2000

To find maximum variance set first derivative equal to 0.

1000-2000x=0

x=\frac{1}{2}

The double derivative of the function at x=\frac{1}{2} is less than 0.

Therefore, x=\frac{1}{2} is a point of maximum.

Thus the maximum variance is:

V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2

V(x)=250

Hence, the maximum variance is 250.

4 0
4 years ago
Question 11 (2.5 points)
Rama09 [41]

Answer:

D

Step-by-step explanation:

The answer is d, because a represents adults, and c represent children. It's $45 per adult, so $45a, and $30 per child, so $30c. a+c is equal to 10, because that's how many tickets were purchased. $45a+$30c=345, because $345 is the total amount spent on tickets.

3 0
3 years ago
Can anyone help me with part C?
finlep [7]

Answer:430

Step-by-step explanation:78 times 3 is 430

3 0
3 years ago
6x2 - 5x - 4 is equivalent to:
Sophie [7]

Answer:

<em>(</em><em>2</em><em>x</em><em> </em><em>+</em><em> </em><em>1</em><em>)</em><em> </em><em> </em><em>(</em><em>3</em><em>x</em><em> </em><em>-</em><em> </em><em>4</em><em>)</em>

Step-by-step explanation:

Solution:

  • 6x² - 5x - 4
  • 6x²- (8 - 3)x - 4
  • 6x²- 8x + 3x - 4
  • 2x (3x - 4) +1 (3x - 4)
  • (2x + 1) (3x - 4)
4 0
2 years ago
If a ship's path is mapped on a coordinate grid, it follows a straight-line path of slope 3 and passes through point (2, 5).
Ugo [173]

Part A: The equation of the ship's path is y=3x-1

Part B: The two ships sails perpendicular to each other.

Explanation:

Part A: It is given that m=3 and point (2, 5)

Substituting these in the slope intercept form, we have,

y-y_{1}=m\left(x-x_{1}\right)

\begin{aligned}y-5 &=3(x-2) \\y-5 &=3 x-6 \\y &=3 x-1\end{aligned}

Thus, the equation of the ship's path in slope intercept form is y=3x-1

Part B: The equation of the second ship is x+3 y-6=0

Let us bring the equation in the form of slope intercept form.

\begin{aligned}3 y &=-x+6 \\y &=-\frac{1}{3} x+2\end{aligned}

Thus, from the above equation the slope is m=-\frac{1}{3}

To determine the two ships sailing perpendicular to each other, we have

m_{1} \times m_{2}=-1

where m_{1}=3 and m_{2}=-\frac{1}{3}

\begin{aligned}3 \times-\frac{1}{3} &=-1 \\-1 &=-1\end{aligned}

Since, both sides of the equation are equal, these two ships sails perpendicular to each other.

3 0
3 years ago
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