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Rama09 [41]
3 years ago
12

Two cars leave the same parking lot, with one heading north and the other heading east. After several minutes, the eastbound car

has traveled 5 kilometers. If the two cars are now a straight-line distance of 8 kilometers apart, how far has the northbound car traveled? If necessary, round to the nearest tenth.
Mathematics
1 answer:
4vir4ik [10]3 years ago
6 0

The northbound car has traveled a distance of 6.2 miles.

Step-by-step explanation:

Step 1:

The eastbound car has traveled a distance of 5 miles and if a straight line is drawn between the two car's positions it would measure 8 miles.

This forms a triangle which has a hypotenuse measuring 8 miles while one of the other sides measures 5 miles.

Assume the distance traveled by the northbound car is x miles.

Step 2:

According to Pythagoras' theorem,

x^{2} +5^{2} =8^{2} , x^{2}  = 8^{2} -5^{2} = 64-25.

x^{2} =39, x=6.2449.

So the northbound car has traveled a distance of 6.244 miles. Rounding this off, we get 6.2 miles.

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Read 2 more answers
1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)
Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that \mu = 8, \sigma = 1.5

What is the probability that you have values between (6.5, 9.5)?

This is the p-value of Z when X = 9.5 subtracted by the p-value of Z when X = 6.5. So

X = 9.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 8}{1.5}

Z = 1

Z = 1 has a p-value of 0.8413.

X = 6.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.5 - 8}{1.5}

Z = -1

Z = -1 has a p-value of 0.1587

0.8413 - 0.1587 = 0.6826

0.6826 = 68.26% probability that you have values in this interval.

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Step-by-step explanation:

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