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2 years ago

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An equilateral triangle has three 60 degree angles and three sides of equal lengths. One equilateral triangle has sides measures

15 centimeters. A second equilateral triangle has sides measuring 25 units. Are the triangles similar?

1 answer:

olga nikolaevna [1]2 years ago

7 0

No it is not possible for them to be similar

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2)<br> 3<br> 3 cm<br> 9 cm<br> Find area

sergey [27]

Answer:
27cm^2

Explanation:
3 x 9 = 27

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2 years ago

What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3? Express your answer as an improper fracti

Likurg_2 [28]

Answer:

242/27

Step-by-step explanation:

Using the formula for the sum, you can fill in the given values and do the arithmetic.

Sn = a1·(r^n -1)/(r -1)

S5 = 6·((1/3)^5 -1)/(1/3 -1) = 6(-242/243)/(-2/3) = 6·(121/81)

S5 = 242/27

_____

Or, you can write the terms and add them up. The sum is ...

6 + 2 + 2/3 + 2/9 + 2/27 = (162 +54 +18 +6 +2)/27 = 242/27

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2 years ago

Basic help :(<br> its math

elena-14-01-66 [18.8K]

Answer:

the slope or rate of change is 8 over 6 or 4 over 3 4/3

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1 year ago

Four servings of yogurt have 12 grams of protein. What is the number of grams of protein per serving?

tester [92]

If there are 12 grams of protein in all, and 4 servings, in order to get the amount of grams per serving you must divide 12 by 4.

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2 years ago

Read 2 more answers

"A student made the following chart to prove that AB2 + BC2 = AC2.

katovenus [111]

Step 3 has an error.

Step-by-step explanation:

Similarity-criteria of triangles:

1. All the corresponding angles of two triangles should be equal.

2. The ratio between the corresponding sides of two triangles should be equal.

In $\triangle ABC$ and $\triangle BDC$

$\angle BAC = \angle DBC \\\angle ACB = \angle BCD$

All the angles of triangle are equal.

∴ $\triangle ABC \sim \triangle BDC$

Since, $\triangle ABC \sim \triangle BDC$

$\frac{AC}{BC}=\frac{AC}{DC}$

$BC^{2}=AC \times DC$

In $\triangle ABC$ and $\triangle BDA$ ,

$\fbox{\begin\\ \angle ABC= \angle BDA = 90^{\circ}\end{minispace}}$

$\fbox{\begin \\\angle BAC = \angle BAD\\\end{minispace}}$

$\angle ACB = \angle ABD$

All the angles of triangle are equal.

∴ $\fbox{\begin\triangle ABC \sim \triangle BDA \end{minispace}}$

∵ $\triangle ABC \sim \triangle BDA$

$\frac{AC}{AB}=\frac{AB}{AD}$

$AB^{2}=AC \times AD$

Now, $AB^{2}+BC^{2}$ can be simplified as,

$AB^{2}+BC^{2}=AC \times AD+AC \times DC\\AB^{2}+BC^{2}=AC(AD+DC)\\AB^{2}+BC^{2}=AC(AC)\\AB^{2}+BC^{2}=AC^{2}$

Learn more:

1. Find the height of the triangle?

brainly.com/question/12989306

2. Which undefined term is needed to define an angle? brainly.com/question/3717797

3. Look at the figure, which trigonometric ratio should you use to find x? brainly.com/question/9880052

Answer Details

Grade: Junior High School

Subject: Mathematics

Chapter: Triangle

Keywords: triangle, similar, similarity, ratio of sides, right triangle, similar triangle, ratio of sides, equal angles, square of hypotenuse, sum, square of legs, sum of square of legs

8 0

2 years ago