C..............................................................
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
x = 15
Step-by-step explanation:
-x = -15
x = -1 × (-15)
<u>x</u><u> </u><u>=</u><u> </u><u>1</u><u>5</u>
Answer:
The first quartile is 5
The third is 8
The interquartile is the difference between the first and third quartile.
The interquartile is 3
Step-by-step explanation:
First, make a list of all the numbers. To find the first quartile, you have to first find the median. The median is the first 7 in the list.
Everything before 7 is the lower percentile of the range.
The firsr quartile is the median of the lower percentile.
The lower list is:
2,3,4,4,5,6,6,6
The median of this list is 5.
The process for finding the third quartile is the same except the list is the higher percentile which is the list of numbers above the median.
