Answer: 480 mL, 600 mL
Step-by-step explanation:
Given
The concentration of the first acid is 75%
The concentration of the second acid is 30%
The final mixture has a concentration of 50%
The final volume is 1080 mL
Suppose x and y be the volume of the first and second acid
Solving the above equations we get
So, the quantity of the first acid is 480 mL and 600 mL for the second mixture.
Answer:
i need them
Step-by-step explanation:
Answer:
See below in bold.
Step-by-step explanation:
For the fair coin Prob(head) = 1/2 and Prob(Tail) = 1/2.
For the biased coin it is Prob(head) = 2/3 and Prob(Tail) = 1/3.
a) Prob(2 heads) = 1/2 * 2/3 = 1/3.
b) Prob(2 tails) = 1/2 * 1/3 = 1/6.
c) Prob(1 head ) = Prob(H T or T H) = 1/2 * 1/3 + 1/2 * 2/3) = 1/6+1/3 = 1/2.
d) Prob (at least one head) = prob (HH or TH or HT) = 1/3 + 1/2 =<em> </em>5/6.
It will be 1 of the 100block
5 of the tens block and 2 single
Hello!
Since the function has no undefined points or domain constants the answer is all real numbers
The answer is all real numbers
Hope this helps!
