(8^-8)(8^3) rewrite the expression in the form 8^n
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Answer:
Step-by-step explanation:
Since it's a coin flip, each coin flip is independent of any other. Each time Steven flips the counter it has the same chance of landing on either side. It's true the on the first throw, and it's true on the 1000th throw.
Even if, extremely improbable, the first 22 flips landed on the blue side, that predicts nothing regarding the outcome of the 23rd flip.
That's all assuming the counter/chip/coin is properly and evenly balanced.... since we have no indication otherwise in the problem definition, we have to assume it's the case.