Answer:
Claim :The proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%.
n = 170
x = 56
We will use one sample proportion test
The proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 36%.
Formula of test statistic =
=−0.8311
Now refer the p value from the z table
P-Value is .202987 (Calculated by online calculator)
Level of significance α = 0.05
Since p value < α
So we reject the null hypothesis .
Hence the claim is true
Answer:
y varies directly as x
y=kx
12=k×6
k=12/6
k=2
When x=8 and y is unknown
y=kx
y=2×8
y=16
Answer:
The answer is x = -13/4
Step-by-step explanation:
-13/4 + 2 / -13/4 +3 = 5
Answer:
P(A U B)= 0.08
Step-by-step explanation:
1.Let:
P(A) as the probability that a psiton has an under-fill defect
P(B) as the probability that a pistón has a porosity defect
P(A ∩ B) the probability of having both defectos
Then:
P(A)=0.05
P(B)=0.04
P(A ∩ B)=0.01
2. The probability that a randomly chosen piston has a defect could be calcularse as the union of the probability of choosing a piston with am under-fill defect and one with porosity defect.
That Is P(A U B)
Aplying the probability properties we have:
P(A U B)= P(A) + P(B) -P(A ∩ B)
Replacing the probabilities:
P(A U B)= 0.05+0.04-0.01
P(A U B)= 0.08
Answer:
c is the correct awnser triangle ghj coordinates