3 years ago

Please help needed immediately

Mathematics

1 answer:

lukranit [14]3 years ago

5 0

All of them or a specific one?

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Lostsunrise [7]

Since $\mathrm M_Y(t)=e^{6(e^t-1}$ , we know that $Y$ follows a Poisson distribution with parameter $\lambda=6$ .

Now assuming $\mu,\sigma$ denote the mean and standard deviation of $Y$ , respectively, then we know right away that $\mu=6$ and $\sigma=\sqrt6$ .

So,

$\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028$

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3 years ago

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earnstyle [38]

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I hope this helps :)

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1 year ago

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stepan [7]

Answer:

0 (zero)

Step-by-step explanation:

${x}^{2} y - y + x {y}^{2} - x \\ = {4}^{2} \times 0.25 - 0.25 + 4 \times {0.25}^{2} - 4 \\ = 16 \times 0.25 - 0.25 + 4 \times 0.0625- 4 \\ = 4 - 0.25 + 0.25 - 4 \\ = 0 \\ \\ \purple {\boxed{ \bold{ \therefore \: {x}^{2} y - y + x {y}^{2} - x = 0}}}$

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3 years ago

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Vesnalui [34]

I am not sure about the answer but all you have to think about is what is 100 divided by 3

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