All categories

3 years ago

Delete this question please. I don't know how to delete this question.

Mathematics

1 answer:

Serhud [2]3 years ago

8 0

I don’t think you can delete questions

You might be interested in

PLZ HELP FAST!!! WILL MARK THE BRAINLIEST -Which of the following is an equivalent form of the compound inequality −33 > −3x

Mazyrski [523]

Answer:

The answer is A

Step-by-step explanation:

4 0

3 years ago

Calculate the measure of arc AC if the measure of arc CD is 170 degrees and arc AB is 80 and AB||CD.

CaHeK987 [17]

Answer:

AC = 55°

Step-by-step explanation:

In this geometry, arcs AC and BD have the same measure. The sum of the parts of arc CD will total the measure of CD.

AC + AB + BD = CD

2AC +80 = 170

AC = 110/2 = 55

The measure of arc AC is 55°.

5 0

2 years ago

Savannah gets paid at home for doing extra chores. Last week, she did 3 loads of laundry and 3 loads of dishes, and her parents

Fynjy0 [20]

Answer:

17$

Step-by-step explanation:

9+8=17$

7 0

3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

3 years ago

Read 2 more answers

The area of a

natali 33 [55]

area=l×w

l=area/w

l=105/5

l=15

perimater=l+w

perimater=15+7

perimeter=22

4 0

2 years ago