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Anna35 [415]
3 years ago
7

Delete this question please. I don't know how to delete this question.

Mathematics
1 answer:
Serhud [2]3 years ago
8 0
I don’t think you can delete questions
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Solve for x: a(x+b)-c=d
tankabanditka [31]
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3 years ago
I am thinking of three numbers. The second number is 5 times the first. The third number is
Fed [463]

Answer:

3, 15, 14

Step-by-step explanation:

x + 5x + ( 5x -1) = 32

11x - 1 = 32

11x = 32 + 1

11x = 33

11x/11 = 33/11

x = 3

therefore

the first number is 3

the second is 5 × 3 = 15

the third number is 15 - 1 = 14

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2 years ago
What's the answer ?​
Leviafan [203]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
The variables A, B, and C represent polynomials where A = x + 1, B = x2 + 2x − 1, and C = 2x. What is AB + C in simplest form?
topjm [15]
AB + C
= (x + 1)(x^2 + 2x - 1)  +  2x
= x^3 + 2x^2 - x + x^2 + 2x - 1 + 2x
= x^3  + 3x^2 + 3x - 1
3 0
3 years ago
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Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -2 (multiplicity 3), 3 (m
Genrish500 [490]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.

The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.

The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).

The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120

(0+2)^3*(0-3)*k = 120

-24k = 120

k = -5

Combining all three conditions, f(x)

= -5(x+2)^3*(x-3)

= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)

= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)

= -5(x^4 + 3x^3 - 6x^2 - 28x -24)

= -5x^4 - 15x^3 + 30x^2 + 140x + 120

6 0
3 years ago
Read 2 more answers
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