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Lynna [10]
3 years ago
5

Jon bought a TV for $359.95, a cell phone for$159.95, a computer for $299.95, and a printer for $89.95. How much did he spend be

fore
taxes?
If the taxes came to $36.55, What was his total cost?
Mathematics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

909.8 /946.35

Step-by-step explanation:

before taxes

add up all the amounts and it equals to 909.8

after taxes

just add the tax(36.55) to the 909.8 and you should get 946.35

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Step-by-step explanation:

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3 years ago
Find dy/dx at (0,0) if x^2cosy-sin(y+4x)+ln(1+x)=0
Ksenya-84 [330]

x^2\cos y-\sin(y+4x)+\ln(1+x)=0

Differentiate both sides with respect to x, treating y as a function of x:

2x\cos y-x^2\sin y\dfrac{\mathrm dy}{\mathrm dx}-\cos(y+4x)\left(\dfrac{\mathrm dy}{\mathrm dx}+4\right)+\dfrac1{1+x}=0

2x\cos y-4\cos(y+4x)-\left(x^2\sin y+\cos(y+4x)\right)\dfrac{\mathrm dy}{\mathrm dx}+\dfrac1{1+x}=0

\left(x^2\sin y+\cos(y+4x)\right)\dfrac{\mathrm dy}{\mathrm dx}=2x\cos y-4\cos(y+4x)+\dfrac1{1+x}

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x\cos y-4\cos(y+4x)+\frac1{1+x}}{x^2\sin y+\cos(y+4x)}

At the point (0, 0), the derivative is

\dfrac{\mathrm dy}{\mathrm dx}(0,0)=\dfrac{0-4\cos0+1}{0+\cos0}=-3

3 0
4 years ago
Using Euler’s formula, how many edges does a polyhedron with 20 faces and 12 vertices have?
astra-53 [7]

Euler's formula for a polyhedron is given by:

\begin{gathered} F+V=E+2 \\ \text{where,} \\ F=\text{faces} \\ V=\text{vertices} \\ E=\text{edges} \end{gathered}

Make E, the subject of the formula:

\begin{gathered} F+V=E+2 \\ E=F+V-2 \end{gathered}

Put F = 20, V = 12, to obtain E,

\begin{gathered} E=20+12-2 \\ E=30 \end{gathered}

Therefore, there are 30 edges

3 0
1 year ago
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8 0
4 years ago
A farmer wants to fence in a rectangular plot of land adjacent to the north wall of his barn. No fencing is needed along the bar
Dmitriy789 [7]

Answer:

Width  = 166.7 ft

Length = 250 ft.

Step-by-step explanation:

From the diagram at the ATTACHMENT

Let us denote the the length of the rectangular area as "x" and

the width of the rectangular area as "y"

Since, cost of the fence on the western side is shared with a neighbor, we can say  it is $7 per foot. Otherwise, it is $14 per foot. The northern length is not fenced.

From the question, we know that the  cost is not to exceed $7000, therefore we can expressed it as

7y + 14x + 14y = 7000

14x + 21y = 7000

Divide through by 14, we have

(x + 1.5) = 500  ------------- eqn (*)            

But the area of the fenced

= A = (x×y)      -------------- eqn  (**)                    

Substitute (*) into (**) we have

A = (500 - 1.5y)*y

= 500y - 1.5y²

In other to maximize the Area, we can find the differential of A

A'(y) = 500 - 3y

At A'(y) = 0.

500-3y= 0

3y=500

y= 166.67 ft

From eqn(*)

(x+ 1.5) = 500

x = 500 - 1.5y

500-1.5(166.67)

= 250ft

Therefore, the dimensions for the plot that would enclose the most area are

Width  of 166.67 ft and Length = 250 ft.

4 0
4 years ago
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