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alexandr402 [8]
10 months ago
5

Using Euler’s formula, how many edges does a polyhedron with 20 faces and 12 vertices have?

Mathematics
1 answer:
astra-53 [7]10 months ago
3 0

Euler's formula for a polyhedron is given by:

\begin{gathered} F+V=E+2 \\ \text{where,} \\ F=\text{faces} \\ V=\text{vertices} \\ E=\text{edges} \end{gathered}

Make E, the subject of the formula:

\begin{gathered} F+V=E+2 \\ E=F+V-2 \end{gathered}

Put F = 20, V = 12, to obtain E,

\begin{gathered} E=20+12-2 \\ E=30 \end{gathered}

Therefore, there are 30 edges

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The system of equations has infinitely many solutions

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

-3x + 3y = 12 ------- eqn 1

y = x + 4 --------- eqn 2

We have to find the solution to the system of equations

We can use substitution method

Substitute eqn 2 in eqn 1

-3x + 3(x + 4) = 12

-3x + 3x + 12 = 12

-3x + 12 = -3x + 12

If we have terms with same terms on both sides of equal sign, then we have infinitely many solutions

Thus the system of equations has infinitely many solutions

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Find a number that is between 2/7 and 4/11 .
Furkat [3]
To answer this problem, one way is to use the calculator and add directly the two numbers and get the average between the two. The answer is 25/77. We can also get this number by getting the LCM of the denominators which is 77. 2/7 is equal to 22/77 while 4/11 is equal to 28/77. 0.5*(22 +28) is equal to 25. Hence the answer is 25/77. 
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Step-by-step explanation:

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