Implement the simulation of a biased 6-sided die which takes the values 1,2,3,4,5,6 with probabilities 1/8,1/12,1/8,1/12,1/12,1/
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Answer:
see explaination
Explanation:
import numpy as np
import matplotlib.pyplot as plt
a = [1, 2, 3, 4, 5, 6]
prob = [1.0/8.0, 1.0/12.0, 1.0/8.0, 1.0/12.0, 1.0/12.0, 1.0/2.0]
smls = 1000000
rolls = list(np.random.choice(a, smls, p=prob))
counts = [rolls.count(i) for i in a]
prob_exper = [float(counts[i])/1000000.0 for i in range(6)]
print("\nProbabilities from experiment : \n\n", prob_exper, end = "\n\n")
plt.hist(rolls)
plt.title("Histogram with counts")
plt.show()
check attachment output and histogram
Microsoft Expression Web 4 is
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Answer:
The variable used is elevenplus
Explanation:
Given
The above code segment
Required
The variable in the code
In Python, variables are used to take inputs, and they are used to storing values.
On the first line of the program, elevenplus is used to get input for age.
Up till the end of the program, no other variable is introduced.
<em>Hence, the variable in the program is </em><em>elevenplus</em>
Answer:
Explanation:dhjyfxdhnjfddhjnvcdfg
Answer:
Explanation:
The code does not fail on the first step since 1900 divided by 4 is actually 475 and has no remainder, meaning that it should return True. The code won't work because the if statements need to be nested in a different format. The correct algorithm would be the following, which can also be seen in the picture attached below that if we input 1900 it would output is not a leap year as it fails on the division by 400 which gives a remainder of 0.75
input_year = int(input())
if input_year % 4 == 0:
if input_year % 100 == 0:
if input_year % 400 == 0:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
else:
print(input_year, "is a leap year")
else:
print(input_year, "- not a leap year")
