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s344n2d4d5 [400]
1 year ago
7

a developer manages an application that interacts with amazon rds. after observing slow performance with read queries, the devel

oper implements amazon elasticache to update the cache immediately following the primary database update. what will be the result of this approach to caching?
Computers and Technology
1 answer:
Vadim26 [7]1 year ago
7 0

Caching will slow performance of the read queries because the cache is updated when the cache cannot find the requested data.

<h3>What is RDS?</h3>

A distributed relational database service provided by Amazon Web Services is known as Amazon Relational Database Service (or Amazon RDS) (AWS).  It is a "cloud-based" web service created to make it easier to set up, manage, and scale a relational database for use in applications. Automatic management is used for administration tasks including patching the database software, backing up databases, and enabling point-in-time recovery. A single API call to the AWS control plane on demand can scale storage and compute resources. As part of the managed service, AWS does not provide an SSH connection to the underlying virtual machine. The AWS Management Console or the Amazon Cloud Watch API both provide performance data for Amazon RDS.

To know more about RDS visit:

brainly.com/question/28209824?referrer=searchResults

#SPJ1

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Does anyone have a rbx account? If they do friend request Tribalchief777
Mila [183]

Answer:

ok, no because this site is for hw

Explanation:

8 0
3 years ago
Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
3 years ago
Part B - Find the solutions for the following Case Study Real World Problems by applying the appropriate concepts that you learn
Monica [59]

Answer:

ok very surprised to hear that

5 0
3 years ago
HELP ASAP!Select all examples of desirable workplace skills, habits, and attitudes.
ddd [48]

Answer:

does not call in sick or miss work frequently

creates a list of solutions for the boss

arrives at work on time or early

waits for supervisor to give directions

works quickly and accurately

shows initiative

communicates effectively

sets clear goals to achieve success

Explanation:

Have a Great Day!!!

7 0
2 years ago
Design (draw a datapath) for a block that will help your processor decide whether to take a branch for different conditions. As
LekaFEV [45]

Answer:

See explaination

Explanation:

Here are the steps taken to draw the diagram!

opcode0 and the opcode1 signals are inverted/not to determine the case whether it is 00, 01, 10, 11.

Then they are 'and'ed with the corresponding Zero/lt signal to confirm if the case is true, for eg. zero = 1 if opcode = 00 (beq).

Then all the cases are 'or'ed to get the Branch signal!

See attachment for the diagram

8 0
3 years ago
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