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Blababa [14]
3 years ago
13

Jeff finds some bugs .he finds 10 fewer grasshopper than cricket.he finds 5 fewer cricketsthan lady bug.if Jeff finds 5 grasshop

pers how many ladybugs does Jeff find?how many crickets does he find? Write two equations to solve the problem
Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

15 crickets; 20 ladybugs

C = G + 10

L= C+5

Step-by-step explanation:

Crickets = C

Ladybugs = L

Grasshoppers = G

We know he found 5 grasshoppers, so:

C = G + 10  --> because he found 10 more crickets than grasshoppers

if we plug in 5 for G (grasshoppers), we can solve for C (crickets):

C= 5+10

<u>15 Crickets</u>

<u />

Now that we know he found 15 crickets we can make our second equation:

L= C+5  --> because he found 5 more ladybugs than crickets

if we plug in 15 C (crickets), we can solve for L (ladybugs):

L= 15+5

<u>20 Ladybugs</u>

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aalyn [17]

Answer:

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Step-by-step explanation:

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2 years ago
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vaieri [72.5K]

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Step-by-step explanation:

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3 years ago
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Find a formula for the general term of the sequence 5 3 , − 6 9 , 7 27 , − 8 81 , 9 243 , assuming that the pattern of the first
Mkey [24]

Answer:

The formula to the sequence

5/3, -6/9, 7/27, -8/81, 9/243, ...

is

(-1)^n. (4 + n). 3^(-n)

For n = 1, 2, 3, ...

Step-by-step explanation:

The sequence is

5/3, - 6/9, 7/27, - 8/81, 9/243, ...

We notice the following

- That the numbers are alternating between - and +

- That the numerator of a number is one greater than the numerator of the preceding number. The first number being 5.

- That the denominator of a number is 3 raised to the power of (2 minus the position of the number)

Using these observations, we can write a formula for the sequence.

(-1)^n for n = 1, 2, 3, ... takes care of the alternation between + and -

(4 + n) for n = 1, 2, 3, ... takes care of the numerators 5, 6, 7, 8, ...

3^(-n) for n = 1, 2, 3, ... takes care of the denominators 3, 9, 27, 81, 243, ...

Combining these, we have the formula to be

(-1)^n. (4 + n). 3^(-n)

For n = 1, 2, 3, ...

4 0
3 years ago
If a car’s speed is 70 miles per hour on a road surface with a drag factor of 0.50 and with a breaking efficiency of 85% (n = .8
hichkok12 [17]

Answer:

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Step-by-step explanation:

The formula for that is given by,

S= \sqrt{30 \times d \times f \times n}

Where,

S is the speed of the car

d is the distance of skid

f is the drag factor for the road surface

n is breaking efficiency as percentage

Putting the values we get,

S^2=  30 \times d \times f \times n

d= \frac{S^2}{30 \times f \times n}

d = \frac{70^2}{30 \times 0.50 \times 0.85} = 384.3 feet

So the length of skid marks would be 384.3 feet.

8 0
3 years ago
2^5/4 = 2^5/2^a = c <br><br> a= b= c=<br> What are the answers pls
monitta

Answer:

mass of 1 mole 2^5/4=2^5/2a=c=0g

Step-by-step explanation:

8 0
2 years ago
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