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Allisa [31]
3 years ago
7

What is the value of 0 squared

Mathematics
2 answers:
ANEK [815]3 years ago
8 0

Answer:

0

Step-by-step explanation:

0×0 is 0 it's not that hard.

vladimir2022 [97]3 years ago
3 0

Answer:

0

Step-by-step explanation:

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66 athletes are running a race. A gold medal is to be given to the winner, a silver medal is to be
Dmitrij [34]

Answer:

274560

Step-by-step explanation:

We can "choose" one of the 66 athletes for the gold medal. That athlete can't win any other medals, so there are 65 athletes left.

We can then "choose" one of the 65 athletes left for the silver medal. That athlete can't win any other medals, so there are 64 athletes left.

We can then "choose" one of the 64 athletes left for the bronze medal.

That leaves us with 66 possible choices * 65 possible choices * 64 possible choices=274560 possible choices

8 0
2 years ago
Find the length of the third side. If necessary, round to the nearest tenth.​
My name is Ann [436]

Answer:

7.8

Step-by-step explanation:

8 0
3 years ago
Which of the following is equivalent to (81m^6)^1/2?
ch4aika [34]
That would be option A 
because square root of 81 is 9 and square root m^6 is m^3.
3 0
3 years ago
Read 2 more answers
A particular isotope has a​ half-life of 74 days. If you start with 1 kilogram of this​ isotope, how much will remain after 150
shtirl [24]

\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}


\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}

6 0
3 years ago
A bag contains 7 marbles, of which I is orange,
lyudmila [28]
6/7 because only one marble is orange
5 0
3 years ago
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