Answer:
First question: LCL = 522, UCL = 1000.5
Second question: A sample size no smaller than 418 is needed.
Step-by-step explanation:
First question:
Lower bound:
0.36 of 1450. So
0.36*1450 = 522
Upper bound:
0.69 of 1450. So
0.69*1450 = 1000.5
LCL = 522, UCL = 1000.5
Second question:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

The project manager believes that p will turn out to be approximately 0.11.
This means that 
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The project manager wants to estimate the proportion to within 0.03
This means that the sample size needed is given by n, and n is found when M = 0.03. So






Rounding up
A sample size no smaller than 418 is needed.
It has a constant variation of 1/2
Answer:
---------
Step-by-step explanation:
x-3= -9
x= -9/ 3
x= -3
( -3x)-5 =16
-3x = 16+5
×= 21/-3
x = -7
Answer:
151.7
Step-by-step explanation:
You find volume with length times width times height. The length is 3.7. The height is 10 and the width is 4.1. When you multiply together you get 151.7.
It will be 23.2
just divide it if u have to round also do that