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Nimfa-mama [501]
3 years ago
8

5 yards minus 4 feet = ?

Mathematics
1 answer:
natima [27]3 years ago
8 0

Answer:

3.66666666 repeating

Step-by-step explanation:

i converted 5 yards to feet, then turned that feet into yards again

answer rounded would be 3.7 yards

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Makovka662 [10]
There is no pictures to choose the right one among tem.

However the equation could be rewritten as follows:

y=√(x²-9)

It is a HORIZONTAL parabola with the following constraint: 3=<x=<-3
5 0
3 years ago
Find the volume of this square<br> based pyramid.<br> 5ft<br> 6 ft<br> [? ]ft
Sav [38]

Answer:

48 ft³

Step-by-step explanation:

To find the height, you can use the slant height and the base.

Using the Pythagorean Theorem and 3 as the triangle's base,

a²+b²=c²

3²+b²=5²

9+b²=25

b²=16

b=4

The height of the pyramid is 4.

Volume formula for the pyramid is \frac{1}{3} *b*h

Inserting our measurements:

\frac{1}{3} *6*6*4=\\2*6*4=\\12*4=\\48

5 0
4 years ago
Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A?
Anvisha [2.4K]
Angle A measures to 59 degrees.
5 0
3 years ago
Solve the system.
Alex777 [14]

Answer:

{x,y,z} = {-18,4,2}

Step-by-step explanation:

Solve equation [2] for the variable  x  

x = -10y + 2z + 18

Plug this in for variable  x  in equation [1]

(-10y+2z+18) + 9y + z = 20

- y + 3z = 2

Plug this in for variable  x  in equation [3]

 3•(-10y+2z+18) + 27y + 2z = 58

   - 3y + 8z = 4

Solve equation [1] for the variable  y  

 y = 3z - 2

Plug this in for variable  y  in equation [3]

  - 3•(3z-2) + 8z = 4

   - z = -2

Solve equation [3] for the variable  z  

 z = 2

By now we know this much :

 x = -10y+2z+18

   y = 3z-2

   z = 2

Use the  z  value to solve for  y  

 y = 3(2)-2 = 4

Use the  y  and  z  values to solve for  x  

 x = -10(4)+2(2)+18 = -18

6 0
3 years ago
A graduated commission employee makes 3.5% interest on the first $50,000 in sales and 6.5% interest on all sales over $50,000. W
masha68 [24]

Answer:

7th Grade ELAR Snapshot

Step-by-step explanation:

6 0
3 years ago
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