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Gala2k [10]
3 years ago
12

Which graph represents the linear function below? y-4= (4/3)(x-2)

Mathematics
1 answer:
svp [43]3 years ago
8 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y-4=(4/3)(x-2)

This is the equation of a line into point slope form

The point is (2.4)

The slope is m=4/3

To plot the line find the intercepts

The y-intercept is the value of y when the value of x is equal to zero

For x=0

y-4=(4/3)(0-2)

y=(-8/3)+4

y=4/3

The x-intercept is the value of x when the value of y is equal to zero

0-4=(4/3)(x-2)

-4=(4/3)x-(8/3)

Multiply by 3 both sides

-12=4x-8

4x=8-12

x=-1

we have the points

(2,4), (0,4/3),(-1,0)

Plot the line

Note With only two points it was necessary to draw the line. The third point was calculated for didactic purposes.

see the attached figure

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Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)
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Answer:

Given: \sin(x) = (4/5).

Assuming that 0 < x < 90^{\circ}, \cos(x) = (3/5) while \tan(x) = (4/3).

Step-by-step explanation:

By the Pythagorean identity \sin^{2}(x) + \cos^{2}(x) = 1.

Assuming that 0 < x < 90^{\circ}, 0 < \cos(x) < 1.

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Given that 0 < \cos(x) < 1:

\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}.

Hence, \tan(x) would be:

\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}.

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